angle U and angle W are vertical angles. If measurement angle u = 6x+11 and measurement angle W = 10x-9, find measurement angle U.

Answers

Answer 1
Answer:

The measure of angle U will be equal to the measure of angle W.

Because W is pronounced "double u", W = 2 * U.

Therefore U = W and U = 2 * W, so both U and W = 0.


Just kidding.

The correct answer is the smallest prime number greater than 40.


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Please help me with this homework equation I don’t understand and need help someone please do step by step
B) How many prime numbers are multiplesof 8?
Transactions to a computer database are either new items or changes to previous items. The addition of an item can be completed less than 100 milliseconds 81% of the time, but only 20% of changes to a previous item can be completed in less than this time. If 30% of transactions are changes, what is the probability that a transaction can be completed in less than 100 milliseconds? Round your answer to two decimal places (e.g. 98.76).
Pls help this is very easy
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Distribute 2(-3x+3x)

Answers

Answer:

-6x+6x

Step-by-step explanation:

Start with:

2(-3x+3x)

Distribute by multiplying:

(2)(-3x) = -6x

(2)(3x)=6x

You're left with:

-6x+6x

(2) (-3x) + (2) (3x) please mark me the brainliest

The upcoming championship high school football game is a big deal in your little town. The problem is, it is being played in the next biggest town, which is two hours away! To get as many people as you can to attend the game, you decide to come up with a ride-sharing app, but you want to be sure it will be used before you put all the time in to creating it. You determine that if more than three students share a ride, on average, you will create the app.You conduct simple random sampling of 20 students in a school with a population of 300 students to determine how many students are in each ride-share (carpool) on the way to school every day to get a good idea of who would use the app. The following data are collected:6 5 5 5 3 2 3 6 2 25 4 3 3 4 2 5 3 4 5Construct a 95% confidence interval for the mean number of students who share a ride to school, and interpret the results.Part A: State the parameter and check the conditions.Part B: Construct the confidence interval. Be sure to show all your work, including the degrees of freedom, critical value, sample statistics, and an explanation of your process.Part C: Interpret the meaning of the confidence interval.Part D: Use your findings to explain whether you should develop the ride-share app for the football game.

Answers

The parameter used in the probability is the average number of students represented by u.

How to calculate the probability?

The confidence interval based on the information will be:

= 3.85 - 2.09(1.348 / ✓20)

= 3.22

Also, 3.85 + 2.09(1.348 / ✓20) = 4.48

The confidence interval simply means that one is 95% confident that the true mean is between 3.22 and 4.48.

Learn more about probability on:

brainly.com/question/24756209

Answer:

a) The parameter of interest on this case is \mu who represent the average number of students in order to create an app.

b) 3.85 - 2.09 (1.348)/(√(20))=3.22  

3.85 + 2.09 (1.348)/(√(20))=4.48  

The 95% confidence interval is given by (3.22;4.48)  

c) For this case we have 95% of confidence that the true mean for the average number of students in order to create an app is between 3,22 and 4.48.

d) We have the following criteria in order to decide: "You determine that if more than three students share a ride, on average, you will create the app"

So then since the lower limti for the confidence interval is higher than 3 we can conclude that at 5% of significance we have more than 3 students share a ride so then makes sense create the app.

Step-by-step explanation:

Part a

The parameter of interest on this case is \mu who represent the average number of students in order to create an app.

Part b

Data: 6 5 5 5 3 2 3 6 2 2 5 4 3 3 4 2 5 3 4 5

n=20 represent the sample size  

\bar X represent the sample mean  

s represent the sample standard deviation  

m represent the margin of error  

Confidence =95% or 0.95

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Calculate the mean and standard deviation for the sample

On this case we need to find the sample standard deviation with the following formula:

s=sqrt{(\sum_(i=1)^20 (x_i -\bar x)^2)/(n-1)}

And in order to find the sample mean we just need to use this formula:

\bar x =(\sum_(i=1)^(20) x_i)/(n)

The sample mean obtained on this case is \bar x= 3.85 and the deviation s=1.348

Calculate the critical value tc  

In order to find the critical value is important to mention that we don't know about the population standard deviation, so on this case we need to use the t distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. The degrees of freedom are given by:  

df=n-1=20-1=19  

We can find the critical values in excel using the following formulas:  

"=T.INV(0.025,19)" for t_(\alpha/2)=-2.09  

"=T.INV(1-0.025,19)" for t_(1-\alpha/2)=2.09  

The critical value tc=\pm 2.09  

Calculate the confidence interval  

The interval for the mean is given by this formula:  

\bar X \pm t_(c) (s)/(√(n))  

And calculating the limits we got:  

3.85 - 2.09 (1.348)/(√(20))=3.22  

3.85 + 2.09 (1.348)/(√(20))=4.48  

The 95% confidence interval is given by (3.22;4.48)  

Part c

For this case we have 95% of confidence that the true mean for the average number of students in order to create an app is between 3.22 and 4.48.

Part d

We have the following criteria in order to decide: "You determine that if more than three students share a ride, on average, you will create the app"

So then since the lower limti for the confidence interval is higher than 3 we can conclude that at 5% of significance we have more than 3 students share a ride so then makes sense create the app.

Plz answer serious answers only

Answers

The answer is 115 degrees too

Blue ribbon taxis offers shuttle service to the nearest airport. You loop up online reviews for blue ribbon taxis and find that there are 17 reviews, six of which report that the taxi never showed up. Is this a biased sampling method for obtaining customer opinion on the taxi service?
If so, what is the likely direction of bias?
explain your reasoning carefully.

Answers

Answer:

In order for a sample to be considered biased, some members of the total population must have either a larger or lower chance of being included in the sample. In this case, your sample contained 17 reviews. It is biased because it was completely voluntary and customers who have a bad experience with a product or service generally tend to express more their dissatisfaction than satisfied customers show their satisfaction.

In marketing, there is a saying that unsatisfied clients talk bad about our product or service 4 times more than satisfied clients. I'm not sure if this saying is exact or not, but all marketing research point in the same direction.

This means that clients that did not get a good service or got no service at all, are more likely to post a review about the company than clients who got a good service. This is what makes the sample biased.

0.8 divided by 405.2

Answers

Answer: 0.00197433

Step-by-step explanation:

In a rally race the lead car is ahead by 1 1⁄2 hours. If the lead car is going 60 mph and the second place car is going 70 mph and starts 1 1⁄2 hours after the lead car, how long will it take to overtake the leader?

Answers

Let t hours be the time the second car is driving untill it overtakes the first car. The nfirst car is t-1(1)/(2) hours on the road.

If the lead car is going 60 mph, then for the t-1(1)/(2) hours  it will go the distance

60\cdot(t-1(1)/(2))\ m.

If the second place car is going 70 mph, then for the hours it will go the distance

70\cdot t\ m.

These distances are equal, then

60(t-1(1)/(2))=70t,\n \n60t-60\cdot (3)/(2)=70t,\n \n10t=90,\n \nt=9\ hours.

Answer: 9 hours