Answer:

The measure of angle U will be equal to the measure of angle W.

Because W is pronounced "double u", W = 2 * U.

Therefore U = W and U = 2 * W, so both U and W = 0.

Just kidding.

The correct answer is the smallest prime number greater than 40.

Please help me with this homework equation I don’t understand and need help someone please do step by step

B) How many prime numbers are multiplesof 8?

Transactions to a computer database are either new items or changes to previous items. The addition of an item can be completed less than 100 milliseconds 81% of the time, but only 20% of changes to a previous item can be completed in less than this time. If 30% of transactions are changes, what is the probability that a transaction can be completed in less than 100 milliseconds? Round your answer to two decimal places (e.g. 98.76).

Pls help this is very easy

HELPPPPPPPPPPPPPPPPPPPPPPPP

B) How many prime numbers are multiplesof 8?

Transactions to a computer database are either new items or changes to previous items. The addition of an item can be completed less than 100 milliseconds 81% of the time, but only 20% of changes to a previous item can be completed in less than this time. If 30% of transactions are changes, what is the probability that a transaction can be completed in less than 100 milliseconds? Round your answer to two decimal places (e.g. 98.76).

Pls help this is very easy

HELPPPPPPPPPPPPPPPPPPPPPPPP

**Answer:**

**Step-by-step explanation:**

Start with:

Distribute by multiplying:

You're left with:

(2) (-3x) + (2) (3x) please mark me the brainliest

The **parameter** used in the **probability** is the average number of **students** represented by u.

The **confidence interval** based on the information will be:

= 3.85 - 2.09(1.348 / ✓20)

= **3.22**

Also, 3.85 + 2.09(1.348 / ✓20) = **4.48**

The **confidence interval** simply means that one is 95% **confident** that the true mean is between 3.22 and 4.48.

Learn more about **probability** on:

**Answer:**

a) The parameter of interest on this case is who represent the average number of students in order to create an app.

b)

The 95% confidence interval is given by (3.22;4.48)

c) For this case we have 95% of confidence that the true mean for the average number of students in order to create an app is between 3,22 and 4.48.

d) We have the following criteria in order to decide: "You determine that if more than three students share a ride, on average, you will create the app"

So then since the lower limti for the confidence interval is higher than 3 we can conclude that at 5% of significance we have more than 3 students share a ride so then makes sense create the app.

**Step-by-step explanation:**

**Part a**

The parameter of interest on this case is who represent the average number of students in order to create an app.

**Part b**

Data: 6 5 5 5 3 2 3 6 2 2 5 4 3 3 4 2 5 3 4 5

n=20 represent the sample size

represent the sample mean

represent the sample standard deviation

m represent the margin of error

Confidence =95% or 0.95

A **confidence interval** is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The **margin of error** is the range of values below and above the sample statistic in a confidence interval.

**Normal distribution**, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

**Calculate the mean and standard deviation for the sample**

On this case we need to find the sample standard deviation with the following formula:

And in order to find the sample mean we just need to use this formula:

The sample mean obtained on this case is and the deviation s=1.348

**Calculate the critical value tc **

In order to find the critical value is important to mention that we don't know about the population standard deviation, so on this case we need to use the t distribution. Since our interval is at 95% of confidence, our significance level would be given by and . The degrees of freedom are given by:

We can find the critical values in excel using the following formulas:

"=T.INV(0.025,19)" for

"=T.INV(1-0.025,19)" for

The critical value

**Calculate the confidence interval **

The interval for the mean is given by this formula:

And calculating the limits we got:

The 95% confidence interval is given by (3.22;4.48)

**Part c**

For this case we have 95% of confidence that the true mean for the average number of students in order to create an app is between 3.22 and 4.48.

**Part d**

We have the following criteria in order to decide: "You determine that if more than three students share a ride, on average, you will create the app"

So then since the lower limti for the confidence interval is higher than 3 we can conclude that at 5% of significance we have more than 3 students share a ride so then makes sense create the app.

The answer is 115 degrees too

If so, what is the likely direction of bias?

explain your reasoning carefully.

**Answer:**

In order for a sample to be considered biased, some members of the total population must have either a larger or lower chance of being included in the sample. In this case, your sample contained 17 reviews. It is biased because it was completely voluntary and customers who have a bad experience with a product or service generally tend to express more their dissatisfaction than satisfied customers show their satisfaction.

In marketing, there is a saying that unsatisfied clients talk bad about our product or service 4 times more than satisfied clients. I'm not sure if this saying is exact or not, but all marketing research point in the same direction.

This means that clients that did not get a good service or got no service at all, are more likely to post a review about the company than clients who got a good service. This is what makes the sample biased.

**Answer: 0.00197433**

**Step-by-step explanation:**

Let t hours be the time the second car is driving untill it overtakes the first car. The nfirst car is hours on the road.

If the lead car is going 60 mph, then for the hours it will go the distance

If the second place car is going 70 mph, then for the hours it will go the distance

These distances are equal, then

**Answer:** 9 hours